A ball is dropped from a high rise platform at t=0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t=18s. What is the value of v? (taking g=10 m/s^2)

Question : A ball is dropped from a high rise platform at t=0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t=18s. What is the value of v? (taking g=10 m/s^2)

(a) 60 m/s

(b) 75 m/s

(c) 55 m/s

(d) 40 m/s

Answer : The Right option is (b)

Solution :

A ball is dropped from a high rise platform at t=0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v
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