Question : 2n boys are randomly divided into two subgroups containing n boys each. The probability that the two tallest boys are in different groups is
(A) \dfrac{n}{2n-1}
(B) \dfrac{n-1}{2\left( n-1\right) }
(C) \dfrac{n-1}{4n^{2}}
(D) none of these
Answer : option (A)
Solution :
