2n boys are randomly divided into two subgroups containing n boys each. The probability that the two tallest boys are in different groups is

Question : 2n boys are randomly divided into two subgroups containing n boys each. The probability that the two tallest boys are in different groups is

(A) \dfrac{n}{2n-1}

(B) \dfrac{n-1}{2\left( n-1\right) }

(C) \dfrac{n-1}{4n^{2}}

(D) none of these

Answer : option (A)

Solution :

2n boys are randomly divided into two subgroups containing n boys each. The probability that the two tallest boys are in different groups is
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